The correct order for acid strength of compou | vedclass

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Question

(D) Acidic strength is directly proportional to the stability of the conjugate base.Stability of the conjugate base depends on the electronegativity o

Vedclass · Accepted Answer

$CH \equiv CH > CH_3 - C \equiv CH > CH_2 = CH_2$

Vedclass · Answer

(D) Acidic strength is directly proportional to the stability of the conjugate base.Stability of the conjugate base depends on the electronegativity of the carbon atom bearing the negative charge.The electronegativity order is $sp$ carbon ($50\% \ s$-character) > $sp^2$ carbon ($33.3\% \ s$-character) > $sp^3$ carbon ($25\% \ s$-character).$1$. $CH \equiv CH$ (ethyne) has $sp$ hybridized carbons.$2$. $CH_3 - C \equiv CH$ (propyne) has one $sp$ hybridized carbon,but the methyl group $(CH_3)$ is electron-donating ($+I$ effect),which destabilizes the conjugate base compared to ethyne.$3$. $CH_2 = CH_2$ (ethene) has $sp^2$ hybridized carbons,which are less electronegative than $sp$ carbons.Therefore,the correct order of acidic strength is $CH \equiv CH > CH_3 - C \equiv CH > CH_2 = CH_2$.

The correct order for acid strength of compounds $CH \equiv CH$,$CH_3 - C \equiv CH$,and $CH_2 = CH_2$ is as follows:

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